3x^2=186

Solution for 3x^2=186 equation:

3x^2=186

We move all terms to the left:

3x^2-(186)=0

a = 3; b = 0; c = -186;
Δ = b2-4ac
Δ = 02-4·3·(-186)
Δ = 2232
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2232}=\sqrt{36*62}=\sqrt{36}*\sqrt{62}=6\sqrt{62}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{62}}{2*3}=\frac{0-6\sqrt{62}}{6}
=-\frac{6\sqrt{62}}{6}
=-\sqrt{62}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{62}}{2*3}=\frac{0+6\sqrt{62}}{6}
=\frac{6\sqrt{62}}{6}
=\sqrt{62}
$